Geometric Sequences for IGCSE Maths
Sequences with a constant ratio between consecutive terms. This subtopic is part of Sequences in the Cambridge IGCSE Mathematics 0580 syllabus (Extended tier only). Understanding geometric sequences i
What You Need to Know
Sequences with a constant ratio between consecutive terms. This subtopic is part of Sequences in the Cambridge IGCSE Mathematics 0580 syllabus (Extended tier only). Understanding geometric sequences is essential for achieving a strong grade in your IGCSE Maths exam.
Understanding Geometric Sequences
A geometric sequence has a constant ratio r between consecutive terms. The nth term formula is Tₙ = ar^(n−1), where a is the first term. The sum of the first n terms is Sₙ = a(rⁿ − 1)/(r − 1) for r ≠ 1. IGCSE Extended tests: finding the nth term, the common ratio, specific terms, and the sum of a geometric series. Real-world applications include compound interest and population growth.
Step-by-Step Method
- 1
Find the common ratio r
Divide any term by the previous one: r = T₂/T₁ = T₃/T₂. Verify it is constant.
- 2
Identify the first term a
The first term is given as the first number in the sequence.
- 3
Write the nth term formula
Tₙ = a × r^(n−1). Substitute a and r.
- 4
Find the sum if required
Sₙ = a(rⁿ − 1)/(r − 1) for r ≠ 1. For |r| < 1, the sum to infinity is S∞ = a/(1−r).
- 5
Verify and interpret
Substitute n = 1, 2, 3 to confirm the formula gives back the original terms.
Worked Example
Question
A geometric sequence starts 6, 18, 54, 162, ... (a) Find the nth term. (b) Find the 7th term. (c) Find the sum of the first 6 terms.
Solution
Part (a): r = 18/6 = 3. a = 6. Tₙ = 6 × 3^(n−1) Part (b): T₇ = 6 × 3⁶ = 6 × 729 = 4374 Part (c): S₆ = 6(3⁶ − 1)/(3 − 1) = 6(729 − 1)/2 = 6 × 728/2 = 6 × 364 = 2184 Answers: (a) 6×3^(n−1) (b) 4374 (c) 2184
Exam Tips for Geometric Sequences
- Common ratio r = T₂ ÷ T₁, not T₂ − T₁ — always divide, never subtract, for geometric sequences.
- The sum formula Sₙ = a(rⁿ−1)/(r−1) is on the formula sheet — but identify a and r correctly first.
- For r between −1 and 1 (e.g. r = 1/2), a sum to infinity exists: S∞ = a/(1−r).
- Compound interest is a geometric sequence: P(1+r/100)ⁿ — recognise this connection in application questions.
Practice Questions
Q1: Find the 8th term of the geometric sequence: 2, 6, 18, 54, ...
Show hint
r = 3, a = 2. T₈ = 2 × 3⁷ = 2 × 2187 = 4374.
Q2: A geometric sequence has first term 80 and third term 20. Find the common ratio and the 5th term.
Show hint
T₃ = 80r² = 20 → r² = 1/4 → r = 1/2. T₅ = 80(1/2)⁴ = 5.
Q3: Find the sum to infinity of 12, 4, 4/3, 4/9, ...
Show hint
r = 1/3, a = 12. S∞ = 12/(1−1/3) = 12/(2/3) = 18.
Frequently Asked Questions
What is geometric sequences in IGCSE Maths?
Sequences with a constant ratio between consecutive terms.
Is geometric sequences in the Core or Extended syllabus?
Geometric Sequences is part of the Extended only syllabus for IGCSE Mathematics 0580.
How do I revise geometric sequences effectively?
Start with the revision notes to understand key concepts, then work through the worked examples step by step. Finally, practise past paper questions under timed conditions. Teacher Rig recommends spending focused revision sessions on geometric sequences rather than trying to cover everything at once.
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