Introductory Trigonometry — Year 9 Practice Questions
Work through these Year 9 practice questions on introductory trigonometry. Try each one before revealing the worked solution.
Questions
Write down the three trigonometric ratios using SOH CAH TOA.
In a right-angled triangle the side opposite the angle is 4 and the hypotenuse is 8. Find the sine of the angle.
Find the angle whose tangent is 1.
A right-angled triangle has an angle of 30° with hypotenuse 10 cm. Find the opposite side. Use sin 30° = 0.5.
A right-angled triangle has opposite 6 and adjacent 8. Find the angle. Use tan⁻¹(0.75) ≈ 36.9°.
Which ratio links the opposite side and the hypotenuse?
A right-angled triangle has an angle of 60° and adjacent side 5 cm. Find the hypotenuse. Use cos 60° = 0.5.
A ramp has opposite 3 m and adjacent 4 m. Find the angle it makes with the ground. Use tan⁻¹(0.75) ≈ 36.9°.
Answers & Worked Solutions
Question 1 Solution
Step 1: SOH: sine = opposite ÷ hypotenuse.
Step 2: CAH: cosine = adjacent ÷ hypotenuse; TOA: tangent = opposite ÷ adjacent.
Answer: sin = O/H, cos = A/H, tan = O/A
Question 2 Solution
Step 1: sin = opposite ÷ hypotenuse = 4 ÷ 8.
Step 2: = 0.5.
Answer: 0.5
Question 3 Solution
Step 1: Use tan⁻¹(1).
Step 2: tan⁻¹(1) = 45°.
Answer: 45°
Question 4 Solution
Step 1: sin 30° = opposite ÷ 10.
Step 2: opposite = 0.5 × 10 = 5 cm.
Answer: 5 cm
Question 5 Solution
Step 1: tan of the angle = 6 ÷ 8 = 0.75.
Step 2: angle = tan⁻¹(0.75) ≈ 36.9°.
Answer: 36.9°
Question 6 Solution
Step 1: Opposite and hypotenuse appear in SOH.
Step 2: So the ratio is sine.
Answer: Sine
Question 7 Solution
Step 1: cos 60° = adjacent ÷ hypotenuse, so 0.5 = 5 ÷ h.
Step 2: h = 5 ÷ 0.5 = 10 cm.
Answer: 10 cm
Question 8 Solution
Step 1: tan of the angle = 3 ÷ 4 = 0.75.
Step 2: angle = tan⁻¹(0.75) ≈ 36.9°.
Answer: 36.9°
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